# PRECONDITION VERIFIED FOR CALL:

# THIS PROGRAM COMPUTES  x * y  AND PLACES THE ANSWER IN  z
x = readInt()
#PREMISES FOR ATTACHED PROOF, IF ANY: 
# True
#PREMISES FOR NEXT LINE: 
# PRECONDITION VERIFIED FOR CALL:
y = readInt()
#PREMISES FOR ATTACHED PROOF, IF ANY: 
# True
#PREMISES FOR NEXT LINE: 
z = 0
#PREMISES FOR ATTACHED PROOF, IF ANY: 
# (z == 0)
#PREMISES FOR NEXT LINE: 
# (z == 0)
count = 0
#PREMISES FOR ATTACHED PROOF, IF ANY: 
# (count == 0)
# (z == 0)
"""{ 1.OK count == 0       premise
     2.OK z == 0           premise
     3.OK z == 0 * y       algebra 2
     4.OK z == count * y   subst 1 3   #algebra 1 2  # algebra solver couldn't prove it  
}""" 
#PREMISES FOR NEXT LINE: 
# (z == (count * y))
# INVARIANT VERIFIED ON LOOP ENTRY
while count != x :
    """{ invariant  z == count * y
         modifies  z, count }"""
    #PREMISES FOR LOOP BODY: 
    # (count != x)
    # (z == (count * y))
    """{ 1.OK z == count * y   premise  }"""  # holds at the start of the body
    #PREMISES FOR NEXT LINE: 
    # (z == (count * y))
    z = z + y
    #PREMISES FOR ATTACHED PROOF, IF ANY: 
    # (z == (z_old + y))
    # (z_old == (count * y))
    """{ 1.OK z == z_old + y         premise
         2.OK z_old == count * y     premise
         3.OK z - y == count * y     algebra 1 2
         4.OK z == (count + 1) * y   algebra 3 
    }"""
    #PREMISES FOR NEXT LINE: 
    # (z == ((count + 1) * y))
    count = count + 1
    #PREMISES FOR ATTACHED PROOF, IF ANY: 
    # (count == (count_old + 1))
    # (z == ((count_old + 1) * y))
    """{ 1.OK count == count_old + 1       premise
         2.OK z ==  (count_old + 1) * y    premise
         3.OK z == count * y               subst 1 2
    }"""   # invariant reproved at end of body
    #PREMISES FOR NEXT LINE: 
    # (z == (count * y))
    # INVARIANT VERIFIED AT END OF LOOP BODY
#PREMISES FOR NEXT LINE: 
# (z == (count * y))
# not (count != x)

# LOOP ENDS
"""{ 1.OK not(count != x)    premise
     2.OK count == x         algebra 1
     3.OK z == count * y     premise
     4.OK z == x * y         subst 2 3
}"""
#PREMISES FOR NEXT LINE: 
# (z == (x * y))