Exercises for Chapter 6, part 1

10 points. Due Monday, April 7

Use the Natural-deduction-proof-checker tool to prove your answers to the following questions, and submit your answers to K-State Online in a zipped folder.


1. In a universe of people, let's make these laws: (i) if someone likes you, you like them back; (ii) if someone is kind, then cindy likes them. Now prove, if don is kind, then he likes cindy:

∀x∀y(Flikes(x,y) —> Flikes(y,x)), ∀x(Fkind(x) —> Flikes(cindy,x)) |− Fkind(don) —> Flikes(don,cindy)

Use ∀e along with the logic rules for ->.


2. "Forall" and "and" interact well with each other. In class we proved,

∀x F(x),  ∀x G(x)  |−  ∀x(F(x) ∧ G(x))
Prove the converse, using both ∀e and ∀i and the rules for ^:

∀x(F(x) ∧ G(x)) |− (∀z F(z)) ∧ (∀z G(z))


3. "Forall" and "not" interact in just this one direction; prove it:

∀y ~F(y) |− ~(∀x F(x))

Next, think about the following so that we can discuss it on Friday:

Say that F means ``has brown eyes.'' How does the above sequent read in English words?

How does the following sequent read in English words: ~(∀x F(x)) |− ∀y ~F(y) ? Is this sequent true for the universe of all living humans? Should our logic rules prove the sequent?


4. "Forall" and "or" interact in just this one direction (prove it):

(∀x F(x)) ∨ (∀x G(x)) |− ∀x(F(x) ∨ G(x))

You cannot prove the converse: ∀x(F(x) ∨ G(x)) |− (∀x F(x)) ∨ (∀x G(x)).
Here's a counter example: Say that the universe consists of all humans. F means ``is left-handed'' and G means ``is right-handed.'' The formula, ∀x(F(x) ∨ G(x)), says everyone is either left- or right-handed. But does this guarantee that (∀x F(x)) ∨ (∀x G(x))?