Exercises for Chapter 6, part 2
10 points.
Due Monday, Dec. 7
Use the ∃i and ∃e rules
to prove these sequents. Use the Natural-deduction-proof-checker
tool, and submit your answers within a zipped folder.
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1.
F(charlie), ∀x(F(x) —> G(x)) |− ∃x( F(x) ∧ G(x))
(some intuition: F == healthy; G == happy)
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2.
∀x (F(x) —> (∃y H(y,x))), ∃x F(x) |− ∃x∃y H(y,x)
(some intution: F == hasAjob; H == isBossOf)
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3.
∃x(F(x) ∧ G(x)) |− (∃y F(y)) ∧ (∃z G(z))
(The converse cannot be proved: Let
F == healthy; G == happy. Perhaps there are two people, one healthy
and one happy, but no one is both healthy and happy at the same time.)
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4.
∃x F(x) |− ¬(∀x ¬F(x))
(some intuition: F == isLeftHanded)